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Mathematics
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\[\frac{ 1 }{ 4xy }\times \frac{ 8x^2 }{3y }\]
3/32x^3 ?
\[8x ^{2}/12xy ^{2}\]
andre how did you get your answer?
2x/3y^2 thts wat i got
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i cross multiplied. is Bronco correct?
ye hes right but andrew you dont croww multiply in this situation .. you only cross mult when its 2 things being added and the denominators dont match
oh
or subtracted, since its multiplied u just multiply across and then reduce and get your answer
Thanks again!
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anything else?
yes :/
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