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Precalculus
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Find the exact value by using a half-angle identity. tan 7pi/8
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So we'll start from here. \[\huge \tan \left(\frac{7\pi}{8}\right)=\tan \left(\frac{\left(\frac{7\pi}{4}\right)}{2}\right)\]
\[\huge \tan \left(\frac{a}{2}\right)=\frac{1-\cos a}{\sin a}\]Using this identity gives us,
\[\huge \frac{1-\cos \left(\frac{7\pi}{4}\right)}{\sin \left(\frac{7\pi}{4}\right)}\]And from here, you just need to remember your special angles on the unit circle.
and that is?
cos(7pi/4) and the sine also, you need to remember those. If you don't know, go back to your chart or whatever you use to figure out the special angles :D It's one of the pi/4 angles, so it'll be something involving sqrt(2)/2's
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