Question

Find all solutions in the interval [0, 2π).

4 sin2 x - 4 sin x + 1 = 0

Answer 1

Do you mean\[4 sin^2 x - 4 sin x + 1 = 0\]?

Answer 2

yes sorry

Answer 3

Nope :)
Treat sinx as a, you'll get
4a^2 - 4a +1 =0
Can you solve this equation?

Answer 4

not really

Answer 5

Can you factorize the left side?

Answer 6

no

Answer 7

Hint: use \(a^2 -2ab +b^2 = (a-b)^2\)