Question

Areas Between Curves:
y=sec^2(x) & y=8cos(x) -pi/3 13 years ago

Answer 1

Am I setting this up correctly?
\[\int\limits_{\frac{ -\pi }{ 3 }}^{\frac{ \pi }{3}} [8 \cos(x)] - [\sec ^{2}(x)] dx\]
I despise Trig Functions