what is quadratic function with only the real two zeros given? x=-1 and x=-3
the reqd eq is (x+1)(x+3)=0 or x^2+x+3x+3=0 or x^2+4x+3=0
thats not one of my answer choices
any one else have an idea
@ktnguyen1 ????
I had the same answer with @matricked
But my choices are y=x^4-4x^3-4x^2-4x-3 y=-x^4+4x^3+4x^2+4x+3 y=x^4+4x^3+3x^2+4x-4 y=x^4+4x^3+4x^2+4x+3
is one of those equal to your answer
Hello?
u asked for a quadratic or apolynomial of 4 degree
u can use factor and reaminder theorem to determine ur answer..
I dont know im just giving you my answer choices?
Im confused and dont know which to pick
or divide each of ur expression on the right(only in x) and then after obtaining another quadratic determine the nature of the result to pick ur reqd choice
do you know what it is because i cant figure it out
i mean to say divide each of ur answer (expression in x) by x^2+4x+3 and check the resultant quadratic to obtain the real or imaginary roots
I have to try synthetic devision to find the answer the last choice is the answer
I get it! Thanks sooo much!
you r wlcm! good night im so sleepy!!!!!!
good Night!!!
Me too!!
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