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Mathematics 14 Online
OpenStudy (anonymous):

y=lxl+2

OpenStudy (anonymous):

how to graph it

OpenStudy (anonymous):

do you know how to graph y=|x| ?

OpenStudy (klimenkov):

Can you graph \(y=x+2\) ?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

well klimenkovs equation is the solution for x>0

OpenStudy (anonymous):

and for x<0 ??

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