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Mathematics 21 Online
OpenStudy (anonymous):

Help please:) i^22

OpenStudy (anonymous):

\[i ^{22}\]

OpenStudy (anonymous):

would it be -1 or -i??

jimthompson5910 (jim_thompson5910):

22/4 = 5 remainder 2 since the remainder is 2, i^(22) = i^2

OpenStudy (anonymous):

Thank you but I'm asking would it stay as -i or -1?

jimthompson5910 (jim_thompson5910):

i^2 = ???

OpenStudy (anonymous):

-1

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