ok I need help with this problem and its due tonight. its goes as such below:
short leg= x
long leg= x+7
Longest leg= 35
this is a squared plus b squared equals c squared and i am hopeless at math help please :/
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OpenStudy (anonymous):
a² + b² = c²
x² + ( x +7)² = 35²
OpenStudy (anonymous):
Ok. Where do I go from there? Apologies math is not my best area.
OpenStudy (anonymous):
Expand ( x +7)² = ....
OpenStudy (anonymous):
(x+7)(x+7)?
OpenStudy (anonymous):
FOIL them out, so that you can simplify with other terms!
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OpenStudy (anonymous):
Ok that is how far I got then I got lost. 2x^2+14x+49=1225
OpenStudy (anonymous):
Great job, indeed :)
OpenStudy (anonymous):
but i need the shortest leg
OpenStudy (anonymous):
You need the form ax² + bx + c = 0 to solve for x :)
OpenStudy (anonymous):
Huh?
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OpenStudy (anonymous):
I thought we were using the Pythagoreom Theorom.
OpenStudy (anonymous):
It is college math. I barely passed in high school.
OpenStudy (anonymous):
We did at the first step :)
OpenStudy (anonymous):
I'm really sorry I get mixed up easily :C
OpenStudy (anonymous):
2x² + 14x + 49 = 1225
Can you make the right side "0"
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OpenStudy (anonymous):
that would end up with the single number being negative is that ok?
OpenStudy (anonymous):
er well if it is allowed to have a negative in there then it would be......
OpenStudy (anonymous):
negative 1176
OpenStudy (anonymous):
which would make the equation 2x^2+14x-1176
OpenStudy (anonymous):
2x² + 14x -1176 = 0
Can you solve for x now?
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OpenStudy (anonymous):
i think so let me try apologies again aspbergers does not make abstract concepts easy in the least
OpenStudy (anonymous):
28,21
OpenStudy (anonymous):
x = 21!
OpenStudy (anonymous):
ok let me try that and see if it works
OpenStudy (anonymous):
awesome thank you thank you
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OpenStudy (anonymous):
Omit the negative value x = -28 ( doesn't make sense for the length )
OpenStudy (anonymous):
it was positive 28 but 21 was right thank you for your help
OpenStudy (anonymous):
No, x = -28, not 28 !
OpenStudy (anonymous):
28 worked as well as 21
OpenStudy (anonymous):
thank you again for your help :)
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