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\[\sqrt{5X-2}=\sqrt{3X}\]
For the first setp, take the square of both sides.
ok.....how do i do that...can those numbers be squared
sqrt(5x-2)^2=sqrt(3x)^2
When take the square you cancel out the exponent with the indice of the root.
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And so you got 5x-2=3x. Just make some algebra and you will solve the equation.
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