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The range of F (x) = 3 sin 2 x is -1≤F(x)≤1 -2≤F(x)≤2 -3≤F(x)≤3
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f(x) = Asin(kx) + c where c is the axis of the curve and A is the amplitude.
so k would be the range? making it 2?
c +- A would be the range.
Which would make it -1 / 1? because 2-3=-1 & 3-2=1. Right?
there's no c, meaning c is 0
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Oh okay, I see now. Thank you so much!!
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