Question

TRIG

Answer 1

\[\frac{\sin^2x+2\cos x-1}{\sin^2 x+3\cos x-3}=\frac{\cos^3x+\cos x}{-\sin^2x}\]

Answer 2

\[-\sin^2x(\sin^2x+2\cos x-1)=\cos x(\cos^2 x+1)(\sin^2 x+3\cos x-3)\]