Question

LAST TWO QUESTIONS. PLEASE HELP

Answer 1

@saifoo.khan

Answer 2

Let's solve the cow one first.

Answer 3

Total area = 36000

Hence:
400G + 1200C = 36,000

Answer 4

If the farmer raises only cows, then: (Total area)/(Area needed for cows)
= 36000/1200

Answer 5

Try the same thing for last part.

Answer 6

36000/400

Answer 7

How do I graph it though?

Answer 8

400G + 1200C = 36,000

Take Goats on y-axis.

Answer 9

Just like"
Ay + Bx = C

Answer 10

Can you show me?

Answer 11

400G + 1200C = 36,000

Ay + Bx = C

You have to make G the subject.

400G = 1200C - 36000

G = (1200C-36000)/400

Answer 12

Thanks :D, so the y-int is 0,-90 and the x-int is 30,0?

Answer 13

Did i typo!

Answer 14

400G + 1200C = 36,000

Ay + Bx = C

You have to make G the subject.

400G = -1200C + 36000

G = (-1200C + 36000)/400