Question

Find the average value fave of the function f on the given interval.

Answer 1

\[16\sec ^{2}(\theta/2), [0,\pi/2]\]

Answer 2

I get 32/pi but it turns out wrong.

Answer 3

\[\frac{32}{\pi}\int \sec^2(\frac{\theta}{2})d\theta\]

Answer 4

i mean
\[\frac{32}{\pi}\int_0^{\frac{\pi}{2}} \sec^2(\frac{\theta}{2})d\theta\]

Answer 5

anti derivative of \(\sec^2(\frac{\theta}{2})\) is \( 2\tan(\frac{\theta}{2})\) maybe that is what went wrong

Answer 6

evaluate at \(\frac{\pi}{2}\) get 2, 0 gives 0 so it should be \(\frac{64}{\pi}\) i think

Answer 7

awesome thanks you so much

Answer 8

yw