Question

Simplify. Help needed with the part b!

Answer 1

i'll solve the first part, simplifying each term.
\[\large 8^{x+2}=8^x 8^2=(8^x)(64)=64(8^x)\]

Answer 2

\[\large 34 (2^{3x})=34((2^3)^x)=34(8^x)\]

Answer 3

numerator: \[\large 8^{x+2}-34(2^{3x})=64(8^x)-34(8^x)=30(8^x)\]

Answer 4

denominator: \[\large \left( \sqrt{8} \right)^{2x+1}=\left( \sqrt{8} \right)^{2x}\left( \sqrt{8}\right)=\left(\left(\sqrt{8}\right)^2\right)^x\sqrt{8}=8^x \sqrt8\]

Answer 5

there is too much math in this thread, so i drew a picture of a bat