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what is the acceleration of a 1000 newton box on a 30 degrees frictionless ramp?
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i think u know the equation\[F=mg\]
\[or, 1000=m \times10\]
or, m=100 kg
now we know that\[F=ma\]
here F will b thw force along the plane of ramp m= mass of the body a=acceleration
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so\[1000 \times \cos 60=100a\]
if u need any more explanation plz ask me
just solve this equation for acceleration a
this f=mg doesn't work here because its inclined plane
funnily, though, since there is no friction, there is no need to take note of how heavy it is. a simply is a component of g |dw:1354520256649:dw| so, \(a=g sin 30\) or, \(a=10*0.5=5ms^{-2}\)
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