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use the system of elimination method to solve the system of equation a +8b=12 a +3b = 2
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R1=(a+8b=12) R2=(a+3b=2) R1-R2 5b=10 b=2
ok if b = 2 then of the answers give it is a ordered pair of (0,2) a solution that infinite solutions or no solutions
you have to go back and solve for a
back- substitution replace b=2 into R1 or R2 and solve for a
I understand that guys im just having trouble i have the subsitution for b in there just lost on what to do next
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a+8(2)=12 solve for a :)
if I understand it right a = 0
no
no ari if your equation is right the a = -4
yes
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so the it would be a ordered pair with (2,-4) being the answer
if it's (a,b) if would be (-4,2)
it*
ok
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