Question

Find the product.
3x^2(2x-7)

Answer 1

3x^(2)(2x-7)

Multiply 3x^(2) by each term inside the parentheses (2x-7).
3x^(2)(2x)+3x^(2)(-7)

Multiply 3x^(2) by the 2x inside the parentheses.
3x^(2)*2x+3x^(2)(-7)

Multiply 3x^(2) by 2x to get 6x^(3).
6x^(3)+3x^(2)(-7)

Multiply 3x^(2) by the -7 inside the parentheses.
6x^(3)-3x^(2)*7

Multiply -3x^(2) by 7 to get -21x^(2).
6x^(3)-21x^(2)