Question

find the coordinates of the focus of the parabola x^2=8(y-1)

Answer 1

vertical parabola x^2=4py => 4p = 8 => p=2
the focus (0, 2)

Answer 2

x^2=4py
and u dont have to care about y-1

Answer 3

hw come ?

Answer 4

we have one more equation of vertical parabola:
(x-h)^2 = 4p (y-k)
with this u can see h=0 and k=1, so the center is ( 0,1). It doesnt affect to p: coordinate of focus

Answer 5

the coordinates are wrong, the answers says (0,3)

Answer 6

so heres the answer:
(x-h)^2 = 4p (y-k) with this u can see h=0 and k=1, so the center is ( 0,1).
so the focus would be (h, k+p)
h=0
k+p = 1+2 = 3
my bad :)

Answer 7

and the focus is on the axis of symmetry