Question

Please help with this!
four fifth x minus three and three fourths x equals two and one half

Answer 1

Alright first thing i would do on this is make your fractions match ...lets forget about x for a moment .... you have 4 /5 and 3 3/4 which as a mixed fraction is 9/4 correct?

Answer 2

I think so

Answer 3

well make 3 3/4 just a straight fraction and what do you get 3 x 4 bc is 3 4/4s and then an extra 3 which makes it 15/4 excuse me

Answer 4

Okay

Answer 5

uh, is that the answer?

Answer 6

no its not..you are trying to find x...sorry my pc turned off

Answer 7

it says equal 2 and 1/2 correct?

Answer 8

yeah

Answer 9

make that into just a fraction

Answer 10

okay

Answer 11

what did you get?

Answer 12

5/2 Is this right?

Answer 13

yes that is correct...the next thing you need to do is give all 3 fractions a common denominator ...4 5 and 2 have what number in common?

Answer 14

20

Answer 15

good ...now to turn them into correct fractions with that number as a denominator ..you multiply the numerator or top by the number you need to make the denominator 20 ..for example ..with 5/2 ...you need the number 10 to make the denominator a 20 correct? ..so you multiply the numerator and get 50/20

Answer 16

Okay

Answer 17

45/20, 75/20/, 50/20

Answer 18

the first one i don't believe is correct

Answer 19

16/20 sorry

Answer 20

yep. now basically still don't put the x in ..but combine like terms..show me the equation without x in it and using those fractions

Answer 21

16/20 - 75/20= 50/20?

Answer 22

yes ...now combine like terms

Answer 23

-53/20= 50/20?

Answer 24

that would be -59/20 but yes

Answer 25

Oops, sorry. I meant to put that.

Answer 26

alright so now you have -59/20x = 50/20

Answer 27

50/-59?

Answer 28

(50/20)/ -(59/20) = x

Answer 29

okay, thank you so much! I appreeciate it!

Answer 30

no problem

Answer 31

can I ask you another question please?

Answer 32

yeah make a new qustion though and close this one

Answer 33

k

Answer 34

wait, I think I got it so far. I'll let you know if I need any help again. Thanks