PLEASE HELP! B is the midpoint of AC and D is the midpoint of CE. Solve for x, given BD = 3x + 5 and AE = 4x + 20. I have the picture if needed.
This is easy
If you could help me that would be great i hate geometry
segment BD is exactly half of segment AE put another way segment AE is twice as long as segment BD
so AE = 2*BD 4x + 20 = 2(3x+5) now solve for x
i know i sound stupid but could you walk me through that
4x+20=2(3x+5) 4x+20=6x+10 ... distribute 4x=6x+10-20 ... Subtract 20 from both sides. 4x-6x=10-20 ... Subtract 6x from both sides. -2x=10-20 ... Combine like terms on the left side -2x=-10 ... Combine like terms on the right side x=(-10)/(-2) ... Divide both sides by -2 to isolate x. x=5 ... reduce
thank you so much!
np
could you help me with another ?
Wow, really.... You needed help with every single step?
Hero, I am way behind right now,and geometry is not my specialty,yes i needed help with the steps.
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