Question

how do you solve for x-intercept in: y = (x - 5)^2 - 4?

Answer 1

x-intercept => y=0
so (x-5)^2 - 4 = 0
=> (x-5)^2 = 4
=> x-5 = +- 2
=> x= 7 and x= 3

Answer 2

wait.. what'd you do with the square?

Answer 3

sqrt 2 sides of equation
sqrt (x-5)^2 = sqrt 4
(x-5)=+-2