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OpenStudy (anonymous):
log x=2 how would i solve that
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OpenStudy (anonymous):
logx=2 10^2=x x=100
OpenStudy (anonymous):
ok, so I have to turn it to exponential form then solve it
OpenStudy (anonymous):
'cause loga=b => 10^b=a
OpenStudy (anonymous):
ok, thanks
OpenStudy (anonymous):
u're welcome
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