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Mathematics 17 Online
OpenStudy (anonymous):

log x=2 how would i solve that

OpenStudy (anonymous):

logx=2 10^2=x x=100

OpenStudy (anonymous):

ok, so I have to turn it to exponential form then solve it

OpenStudy (anonymous):

'cause loga=b => 10^b=a

OpenStudy (anonymous):

ok, thanks

OpenStudy (anonymous):

u're welcome

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