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A 1.10-kg wrench is acting on a nut trying to turn it. The length of the wrench lies directly to the east of the nut. A force 150.0 N acts on the wrench at a position 15.0 cm from the center of the nut in a direction 30.0° north of east. What is the magnitude of the torque about the center of the nut?
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might help to draw out a picture
|dw:1354625870663:dw|
torque is equal to the perpendicular force times the distance it is applied ...
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