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How is x squared + 3c - ( x squared - 3x)= 6x
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plus 3x**
\(x^2 +3c-(x^2 +3x)=6x\) are you solving for x, and c is a constant?
\[x^2 + 3x - ( x^2 -3x ) = 6x\] (opening bracket and multiplying with -ve) \[x^2 + 3x - x^2 + 3x =6x \] (x^2 - x^2 =0 ) \[6x = 6x\]
ah. so c is x...............
exactly;)
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wait. that means it's solve for c. lol
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