Question

Solve |x| + 7 < 4.



{x | x < -11 or x > -3}
{x | -3 < x < 3}
Ø

Answer 1

no realroots

Answer 2

subtract 7 from both sides first
then since the right is negative, but the absolute value is never negative, there is no solution

Answer 3

abs(x)+7 is less than 4
abs(x) is less than 4 - 7
abs(x) is less than -3
therefore, x is less than plus or minus 3