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Mathematics 7 Online
OpenStudy (anonymous):

CHECK MY WORK, PLEASE! Solve: 16 < 3x + 1 < 4 16 < 3x + 1 < 4 16 < 3x + 1 -1 to both sides 15<3x /3 to both sides 5

OpenStudy (anonymous):

It's wrong. First of all, 16 cannot be less than 4.

OpenStudy (anonymous):

Is there a mistake in the question?

OpenStudy (anonymous):

??? I thought with these types of problems you have to split them up from 16 < 3x + 1 < 4 to two equations; 16 < 3x +1 and 3x +1<4.

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