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OpenStudy (anonymous):
you are amazing, thank you so much! you made it clear too!
OpenStudy (anonymous):
Yep
OpenStudy (anonymous):
can you help me with one more?
OpenStudy (anonymous):
Sure
OpenStudy (anonymous):
What are the real or imaginary solutions of the polynomial equation?
27x3 + 125 = 0
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OpenStudy (anonymous):
27x^3+125=0 is the equation?
OpenStudy (anonymous):
yupp
OpenStudy (anonymous):
Do you also want the work?
OpenStudy (anonymous):
yes please, that would actually help! i understand it better
OpenStudy (anonymous):
okay.
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OpenStudy (anonymous):
27x^3+125=0.... so factor the left side
(3x+5)(9x^2-15x+25)=0
Now split each side
(3x+5)=0
(9x^2-15x+25)=0
And solve each one separably.
For the first one: (3x+5)=0 ... subtract 5 and then divide by 3
You get x=-5/3
Now solve the other part using the quadratic equation.
OpenStudy (anonymous):
Do you know how to use the quadratic formula? and do you follow so far?
OpenStudy (anonymous):
yes!
OpenStudy (anonymous):
so i did the quadratoc formula and my answers i got
OpenStudy (anonymous):
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OpenStudy (anonymous):
and the other answer the same thing but its a minus sign between them am i right?