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Mathematics 14 Online
OpenStudy (anonymous):

A cylindrical piece of iron pipe is shown below. The wall of the pipe is 0.75 inch thick, and the pipe is open at both ends. What is the approximate inside volume of the pipe? 398 cubic inches 603 cubic inches 565 cubic inches 412 cubic inches

OpenStudy (anonymous):

jimthompson5910 (jim_thompson5910):

radius of outer cylinder: 8/2 = 4 radius of inner cylinder: 4 - 0.75 = 3.25

jimthompson5910 (jim_thompson5910):

Volume of inner cylinder V = pi*r^2*h V = pi*(3.25)^2*12 V = ???

OpenStudy (anonymous):

it would be 398, right? @jim_thompson5910

jimthompson5910 (jim_thompson5910):

if you round to the nearest whole number, yes

OpenStudy (anonymous):

so that would be my answer for the problem?

jimthompson5910 (jim_thompson5910):

yes

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