Question

Find the value of k so that the line passing through the given points has slope m. Write an equation of the line in point-slope form.
(k, 4k), (k+2,3k), m = -1

Answer 1

given
(k, 4k), (k+2,3k), m = -1

m=(4k-3k)/(k-(k+2))
m=1k/(-2)=-1 continue here and find k=?

now using the point (k, 4k)=(?,?) using the value of k, and using m=-1
set up an Equation using the formula
y - y1= m (x - x1)
y - ? = -1 (x - ?) then simplify this to make point slope form

Answer 2

Would it be y+2 = 1/-2 (x - .5) ?

Answer 3

using the points and slope given

(k, 4k), (k+2,3k), m = -1

(4k-3k)
m= ----------
(k-(k+2))

1k
m = ----- = -1
-2

therefore k=2
now the points are
(k, 4k)=(2,8) why?
(k+2,3k)=(4,6) why?

now using either of these points
(2,8) or (4,6) and
using the formula of
point-slope form.

y - y1= m( x - x1)
y - 8 = -1(x - 2 ) yes or no?

Answer 4

Because k=2 and it's just k in the first x and 4 times 2 is 8 so it's (2,8) and 2+2 = 4 and 3 times 2 = 6 so it's (4,6). Yes that's correct! Thank you! I just wasn't sure how you would find it. I kept getting 1 over -2. I just couldn't figure out what to do with it.