Question

Solving trig equations - i know the first few steps, but i'm not sure about the answer:
2sin^2(2x)=1 (2x)=y
2sin^2(y)=1
sin^2(y)=(1/2)
sin(y)=+/- (sqrt 2)/2 = (pi/4 , 5pi/6 , 5pi/4 , 7pi/4) The question is: is this my final answer or do I have to set my answer equal to 2x?

Answer 1

the interval is (0 to 2pi)