Question

the equation of a circle when endpoints of a diameter at (-2,-9) and (0,-5)

Answer 1

when the ends of the diameter are given as(x1,y1) and (x2,y2)
the eq of circle is given by (x-x1)(x-x2) +(y-y1)(y-y2)=0
i hope rest u will be able to do

Answer 2

idk what the heck u just did

Answer 3

the eq of the circle is given by
(x+2)(x-0)+(y+9)(y+5)=0
or x^2+2x+y^2+14y+45=0
or x^+y^2+2x+14y+45=0