Question

solve using the quadratic formula: (x-3)(x+1)=-6

Answer 1

first u have to multiply ad simplify
thus we have x^2-2x-3=-6
or x^2-2x-3+6=0
or x^2-2x+3=0
x^2-2x+1 +3-1=0
(x-1)^2 +2=0
(x-1)^2-2i^2=0 (i=sqrt(-1))
(x-1+isqrt(2))(x-1-isqrt(2))=0
hence x=1+i sqrt(2) ,1-i sqrt(2)