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OpenStudy (anonymous):
4. The diameters of grapefruits in a certain orchard are normally distributed with a mean of 6.95 inches and a standard deviation of 0.75 inches. Show all work. (A) What percentage of the grapefruits in this orchard have diameters less than 6.6 inches? (B) What percentage of the grapefruits in this orchard are larger than 6.9 inches?
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OpenStudy (kropot72):
(A) Work out the z-score for 6.6 inches. Then use a standard normal distribution table to find the required percentage. (B) Work out the z-score for 6.9 inches. Then use a standard normal distribution table to find the required percentage.
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