Question

x^4 *y^4 = 16, normal (2,1). Find the slope of the the line that is normal to the curve. A) y = 1/8x B) y = -1/2 x +2 C) y = -2x+5 D) y = 2x-3

Answer 1

y'=Y/X=1/2
this is the slope of tangent at the point (2,1)
slope of the normal will be -(1/y')
so slope of normal is -2
equation becomes
Y=-2X + c
ut the values of X and Y
1=-4+c
c=5
therefore equation is
Y=-2X+5