Question

On a given day, the flow rate F (cars per hour) on a congested roadway is F=(v)/(22+0.02v^2), where v is the traffic in miles per hour. What speed will maximize the flow rate on the road?

Answer 1

look for the value of v that df/dv=0
df/dv=[(22+0.02v**2)-v(0.04v)]/den**2
22-0.02v**2=0
v=sqrt(1100)=33.16 miles/hour