Question

Differentiate: y = (v^3 - 2v[sqrt[v]])/v

Answer 1

\[\large y = \frac{v^3 -2v \sqrt{v}}{v}\]
I would first simplify by factoring:
\[\large y= \frac{\cancel v (v^2-2\sqrt{v})}{\cancel v}\]
Then convert any roots to exponential form:
\[\large y= v^2-2v^{\frac{1}{2}}\]

Hopefully it is manageable from here

Answer 2

nice work

Answer 3

nice work..tengs :)