Question

IM DOING applications with polynomials:::
1:) Solve: x4 − 5x3 + 11x2 − 25x + 30 = 0


2:) Solve the equation: x2 + 5x + 22 = 0


3:) Solve: x3 − 2x2 + 10x + 136 = 0

Answer 1

please~~~

Answer 2

It kind like complicated to write down all the work, and i just online by my cell phone. I did your works. Do you want i give you the problem after I factored?

Answer 3

please ! i need the answer mainly

Answer 4

Ok
1. (x-2)(x-3)(x^2+5)=0

Answer 5

Im going to do 2.

Answer 6

2. Use quadratic formula:x= (-5+,-3isqrt (7))/2

Answer 7

These are the answer choices for # 2

0

-2.5

15.75

No solution

Answer 8

the discriminant of #2 is

D = b^2 - 4ac

D = (5)^2 - 4(1)(22)

D = 25 - 88

D = -63

a negative discriminant means what?

Answer 9

So #2 it just has the imagine solution, it is not real solution for it.------>no solution

Answer 10

These are the answer chocies for #3

-4, 3 − 5i, 3 + 5i

-2, 3 − 5i, 3 + 5i

-4, 8

No solution

Answer 11

x^3 - 2x^2 + 10x + 136 = 0


(-2)^3 - 2(-2)^2 + 10(-2) + 136 = 0


-8 - 2(4) + 10(-2) + 136 = 0


-8 - 8 - 20 + 136 = 0


100 = 0 which is FALSE, so x = -2 is NOT a root.


so that rules out choice B

Answer 12

alright so?

Answer 13

x^3 - 2x^2 + 10x + 136 = 0


(-4)^3 - 2(-4)^2 + 10(-4) + 136 = 0


-64 - 2(16) + 10(-4) + 136 = 0


-64 - 32 - 40 + 136 = 0


0 = 0 which is TRUE, so x = -4 is a root.


that means that the answer is either A or C

Answer 14

plug in x = 8 and see if it makes the polynomial zero

Answer 15

it does

Answer 16

no it doesn't, try it again

Answer 17

oops. a is correct

Answer 18

yes

Answer 19

for #1, use wolfram alpha to get

http://www.wolframalpha.com/input/?i=x^4-5*x^3%2B11*x^2-25*x%2B30+%3D+0

so from that page, the 4 answers are what you see attached