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Mathematics 10 Online
OpenStudy (anonymous):

factor m^3+12m^2+36 m

OpenStudy (raden):

m is common factor, can u factor out now

OpenStudy (anonymous):

m^2+12m+36

OpenStudy (raden):

yes, correct be m(m^2+12m+36) now, u have to factoring again for (m^2+12m+36), find two number when added get 12 and multiply be 36, what's that numbers

OpenStudy (anonymous):

6,6

OpenStudy (anonymous):

so m(m^2+6m)(6m+36)

OpenStudy (raden):

it mean m^2+12m+36 = (m+6)(m+6) so, all the factos be m(m+6)(m+6)

OpenStudy (anonymous):

sweet it works thanks

OpenStudy (raden):

welcome

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