Question

What are all the real zeroes y = (x –12)^3 – 7? If an explanation could be provided too it'd be appreciated.

Answer 1

zeros mean when y = 0

Answer 2

Simplify the function first. It'll be easier.

Answer 3

so set y = 0 meaning 0 = (x^2 - 24x + 144) - 7

Answer 4

wooops it's cube

Answer 5

set y =0. 0 = (x-12)^3 - 7 => (x-12)^3 = 7 => x-12 = cube rt (7) => x =[ cube rt (7) ]+12

Answer 6

set y=0 then (x-12)^3=7, this gives x=12+cuberoot(7)=13.91(approx).