Question

solve (4y+8)(3y-2)

Answer 1

\[(4y+8)(3y-2)=4y(3y-2)+8(3y-2)\]
\[\qquad\qquad\qquad=4y\times3y-4y\times2+8\times3y-8\times2\]

Answer 2

to solve or to expand it ?

Answer 3

hmm how to solve if its not an equation?

Answer 4

that's right @UnkleRhaukus :)

Answer 5

(4y+8)(3y-2) =

Use the FOIL to expand.

4y times 3y + 4y times -2 + 8 times 3y + 8 times -2 =

12y^2 -8y +24y - 16 =

12y^2 + 16y - 16

Done!