Question

find the coordinates of the turning points of y=2x^2(3-x) and determine their nature.

Answer 1

find the derivative and equate to zero
y=2x^2(3-x)
y = 6x^2 - 2x^3

do you know how to differentiate this?

Answer 2

use the formula

if y = ax^n
y' = anx^(n-1)

so for example if

y = 3x^4
y' = 3*4 x^(4-1)
= 12 x^3