Question

I need help solving Quadratic Equations. Comment if you know how to solve them so I can give you the problems.

Answer 1

many ways to solve a quadratic:
Quadratic formula (always works)
Factoring (does not always work especially if the quadratic is prime)
complete the square (too tedious)
square root property but it has to be set up a certain way
graphing method, look at the graph to see the number of solutions

Answer 2

Solve:
3y2 - 48 = 0

Answer 3

using the quadratic formula attached , we have the form ax^2 + bx + c = 0 .. here we have a = 3 , b = 0 , c = -48 , substitute into the formula and you will get the result y = 4 or y = -4

Answer 4

What about this one:

5x2 - 45 = 0

Answer 5

you do the same steps using the quadratic formula , here we have a = 5 , b = 0 , c = -45 so by substituting in the quadratic formula you get x = 3 or x = -3

Answer 6

What about this one?