Question

I need help please it is really IMPORTANT!!
Please and Thank You

Answer 1

wuts up?

Answer 2

find the equation of the line that passes through (8,15) and is perpendicular to y = 4/3x + 6

Answer 3

Just doing math, do I know you because I feel like I do..

Answer 4

@ethompsonn

Answer 5

slope of the line perpendiculer to
y=4/3x+6
will be -3/4
so the equation of that line is
Y=-3X/4 + c
we know that it pass through (8,15) so plug it into equation
15=-6+c
c=21
so the equation is
Y=-3X/4 +21

Answer 6

OMG thank you so much...

Answer 7

you'r welcome

Answer 8

@binary3i

At what point does the line given by the following equation cross the y-axis?
y = 6/9x+ 8

Answer 9

i dint get you?
do you mean at what point the line cuts the y axis?

Answer 10

It crosses the y axis, and the y value is 0. So set y to 0 in your equation, and solve for x.

Answer 11

y=0 in equation
0=6/9x+8
x=-12
so the point is (-12,0)