Question

Part 1:
Solve the following system of equations. Please show your work to receive full credit.
x - y = 16
2x + y = 2

Part 2:
Explain which method you chose to solve the system and why you felt it was the best choice.

Answer 1

Add equation 1 to equation 2. Since you have -y in eq 1 and y in eq 2, the y's will cancel out and you can solve for x easily.
x - y = 16
2x + y = 2
---------
3x = 18
Divide both sides by 3
x = 6
Now substitute x into eq 1:
6 - y = 16
Subtract 6 from both sides:
-y = 10
divide both sides by -1
y = -10

Answer 2

I would choose substitution method as the first equation is simple to use:
x=y+16
substituting this in second equation it then becomes 2(y+16) + y = 2
2y +32 +y = 2
3y +32 = 2
3y = -30
y = -10

Answer 3

The above was part 1.
Part 2 is Elimination method because by adding the equations as they are you eliminate y and it's easy to solve for x.

Answer 4

Then substitute 10 for y in the first equation getting: x-(-10) =16
x+10=16
x=6

Answer 5

Thank you guys for your help! :)