The magnitude of the vectors F~
is 28 N, the
force on the right is applied at an angle 60
◦
and the the mass of the block is 79 kg.
If the surface is frictionless, what is the
magnitude of the resulting acceleration?
Answer in units of m/s
2

Question

The magnitude of the vectors F~
is 28 N, the
force on the right is applied at an angle 60
◦
and the the mass of the block is 79 kg.
If the surface is frictionless, what is the
magnitude of the resulting acceleration?
Answer in units of m/s
2

anonymous · Answer

attachment

anonymous · Answer

F=ma
28 N*cos(60)=79 kg * a

Then solve for a.
Hope that helps.