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Find values of a and k for a parabola containing the points given: y - k = a(x + 3)2; (-5,1) and (1,7) A. a = 2; k = 3 B. a = 0.5; k = -1 C. a = .5; k = 3 D. a = 2; k = -1
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\[y=a(x+3)^2+k\] \[1=a(-5+3)^2+k\] \[1=4a+k\] is one equation
\[7=a(1+3)^2+k\] \[7=16a+k\] is the second equation
solve \[4a+k=1\]\[16a+k=7\] for \(a\) and \(k\)
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