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The vertex of the function x2 + 6x − 16 = 0 is (-3, -25). Answer True False
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@artofspeed help
@yummydum Help?
It true! @yummydum
do \(\large{x={-b\over2a}}\) to find the x value of the vertex:\[{-6\over2(1)}~~~~\implies~~~~{-6\over2}~~~~\implies~~~~{x=-3}\]now put that into the polynomial \( x^2 + 6x − 16 \):\[ x^2 + 6x − 16~~~~\implies~~~~(-3)^2+6(-3)-16\]\[9-18-16\]\[y=-25\] so yes the vertex is at (-3,-25), True
Thanks! (:
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