Check my work?
7x - 3y = 20
5x + 3y = 16
I added them together
12x + 0 = 36
12x = 36
Divided by 12
x = 3
Substitute 3 into either equation.
7(3) - 3y = 20
21 - 3y - 21 = 20 - 21
-3y = -1
Divide each side by -3
y = -1/3
(3, -1/3)?

Question

Check my work? 
7x - 3y = 20
5x + 3y = 16
I added them together
12x + 0 = 36
12x = 36
Divided by 12
x = 3
Substitute 3 into either equation.
7(3) - 3y = 20
21 - 3y - 21 = 20 - 21
-3y = -1
Divide each side by -3
y = -1/3
(3, -1/3)?

anonymous · Answer

Looks good except the y value is not negative. It should look something like (3, 1/3)

anonymous · Answer

Okay, thank you!

anonymous · Answer

Yep

eyust707 · Answer

7(3) - 3y = 20
21 - 3y - 21 = 20 - 21
-3y = -1
all good..
then
y = -1/-3
y= 1/3

anonymous · Answer

Wait do either of you know what method this is called?