find the solution of this sytsem of equations8x-4y=-32 & -3x+4y=-42
Add both equations together, this will eliminate the y variable and you'll just have to solve for x. Then substitute the value of x back into one of the equations and solve for y.
makes ni sence
First step. Add both equations together: 8x -4y = -32 +(-3x+4y=-42) ----------------- What do you get?
like add what and what together -32 and -42
All of them: 8x-3x=how many x's -4y+4y=how many y's -32-42= what number
X=5 Y=0 AND NUMBERS=10
With the new values your form a new equation. 5x=10 Next step: Solve for x
would it be 5?
No. According to the equation it's a number that multiplied times 5 will give you 10.
2?
Right. Now next step. Substitute that value in place of the x's in either one of the two original equations. 8x-4y=-32 8(2)-4y=-32 Do the operation, then solve for y.
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