Question

Determine the sum for the arithmetic series:

n = 41, t1 = 17, t41 = 245

A. 303
B. 5,371
C. 10,824
D. 7,105

Answer 1

A(n) = A(1) + a (n-1)
A(41) = A(1) + a (41-1)
a = (245 -17)/40
a = 5.7
A(n) = 17 + 5.7(n-1)
or = 11.3 + 5.7n
S(n) = ∑ (11.3 + 5.7i)
= 11.3 n + 5.7 (½) (n)(n+1)
S(41) = 11.3 (41) + 5.7 (½) (41)(42)
= 5371

Answer 2

Thanks so much!

Answer 3

your welcome again =)

Answer 4

Lol :)

Answer 5

I have another question for you